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java 创建一个char类型的数组,存储‘A‘-‘Z‘(26个字母)
阅读量:341 次
发布时间:2019-03-04

本文共 625 字,大约阅读时间需要 2 分钟。

public class Number {    public static void main(String[] args){        char[] chars = new char[26];        //int index = 0;        //for (char i = 'A'; i < 'Z'; i++){        //    chars[index] = i;        //    index++;        //}        for (int i = 0; i < chars.length; i++){            //'A' + i 表达式的结果是int类型,需要强制转换为char类型            //byte,short,char在参与算数运算时,会自动转为int类型,单独计算也是            //char c1 = 'a'; char c2 = 'b'; int i1 = c1 + c2;(这里不能使用char类型变量接收结果)            chars[i] = (char)('A' + i);        }        for (char aChar : chars) {            System.out.print(aChar);        }    }}//输出ABCDEFGHIJKLMNOPQRSTUVWXYZ

 

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